derivative (x^3)/3+x^2+4x-10

解答

导数

\frac{x ^{3}}{3} + x^{2} + 4 x - 10

x^{2} + 2 x + 4

求解步骤

\frac{d}{d x} (\frac{x ^{3}}{3} + x^{2} + 4 x - 10)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (10)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (10) = 0

= x^{2} + 2 x + 4 - 0

化简

= x^{2} + 2 x + 4

\frac{d}{d x} (\frac{3 x ^{2}}{( x ^{2} + x ) ^{3}})

a re a 17 e^{0.02 t}, 21 e^{0.02 t}, [0, 50]

\frac{\partial}{\partial y} (x cos (y))

\frac{d y}{d x} = 3 x^{2} y

t a y l or e^{2 x}