(dy)/(dx)+3y=2xe^{-3x}

解答

\frac{d y}{d x} + 3 y = 2 x e^{- 3 x}

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

求解步骤

\frac{d y}{d x} + 3 y = 2 x e^{- 3 x}

求解线性方程:

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

n = 0 \sum \infty \frac{1}{1.0 2 ^{n}}

x d x - y d y = 0

\frac{\partial}{\partial z} (e^{y})

im pl i c i t \frac{d y}{d x}, cos (x - y) = x e^{x}

\frac{d ^{2}}{d x ^{2}} (- t^{3} + 15 t^{2} + 21 t)