What is the limit as x approaches 0 of 2xln(x^2) ?

The limit as x approaches 0 of 2xln(x^2) is diverges

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limit as x approaches 0 of 2xln(x^2)

x \to 0 lim (2 x ln (x^{2}))

diverges

Solution steps

x \to 0 lim (2 x ln (x^{2}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2 x ln (x^{2})) = 0

x \to 0 - lim (2 x ln (x^{2})) = 2 \cdot 0

Does not exist

= diverges

What is the limit as x approaches 0 of 2xln(x^2) ?
The limit as x approaches 0 of 2xln(x^2) is diverges