What is the integral of sin(2x)sin(x) ?

The integral of sin(2x)sin(x) is 2/3 sin^3(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sin(2x)sin(x)

\int sin (2 x) sin (x) d x

\frac{2}{3} sin^{3} (x) + C

Solution steps

\int sin (2 x) sin (x) d x

Rewrite using trig identities

= \int 2 sin^{2} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin^{2} (x) cos (x) d x

Apply u-substitution

= 2 \cdot \int u^{2} d u

Apply the Power Rule

= 2 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= 2 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

2 \cdot \frac{sin ^{3} ( x )}{3} : \frac{2}{3} sin^{3} (x)

= \frac{2}{3} sin^{3} (x)

Add a constant to the solution

= \frac{2}{3} sin^{3} (x) + C

What is the integral of sin(2x)sin(x) ?
The integral of sin(2x)sin(x) is 2/3 sin^3(x)+C