(\partial)/(\partial x)(ln(2+x^2+y^2))

Lösung

\frac{\partial}{\partial x} (ln (2 + x^{2} + y^{2}))

\frac{2 x}{2 + x ^{2} + y ^{2}}

Schritte zur Lösung

\frac{\partial}{\partial x} (ln (2 + x^{2} + y^{2}))

Behandle

y

als Konstante

Wende die Kettenregel an:

\frac{1}{2 + x ^{2} + y ^{2}} \frac{\partial}{\partial x} (2 + x^{2} + y^{2})

= \frac{1}{2 + x ^{2} + y ^{2}} \frac{\partial}{\partial x} (2 + x^{2} + y^{2})

\frac{\partial}{\partial x} (2 + x^{2} + y^{2}) = 2 x

= \frac{1}{2 + x ^{2} + y ^{2}} \cdot 2 x

Vereinfache

\frac{1}{2 + x ^{2} + y ^{2}} \cdot 2 x : \frac{2 x}{2 + x ^{2} + y ^{2}}

= \frac{2 x}{2 + x ^{2} + y ^{2}}

\frac{\partial}{\partial y} (ln (y - 3 x))

\int - 24 t e^{- 3 t} d t

\frac{d ^{2}}{d x ^{2}} (4 x)

\int \frac{x ^{2} - x + 2}{x ^{4} + 4 x ^{2} + 3} d x

\int i n^{2} x d x