What is the tangent of f(x)=(x^2+36)(2x+21),\at x=-4 ?

The tangent of f(x)=(x^2+36)(2x+21),\at x=-4 is y=676

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tangent of f(x)=(x^2+36)(2x+21),\at x=-4

tangent of

f (x) = (x^{2} + 36) (2 x + 21), at x = - 4

y = 676

Solution steps

Find the tangent point:

(- 4, 676)

Find the slope of

f (x) = (x^{2} + 36) (2 x + 21) : \frac{df ( x )}{d x} = 6 x^{2} + 42 x + 72

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(- 4, 676) : y = 676

y = 676

What is the tangent of f(x)=(x^2+36)(2x+21),\at x=-4 ?
The tangent of f(x)=(x^2+36)(2x+21),\at x=-4 is y=676