integral of 4x+4

Lösung

\int 4 x + 4 d x

2 x^{2} + 4 x + C

Schritte zur Lösung

\int 4 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x + \int 4 d x

\int 4 x d x = 2 x^{2}

\int 4 d x = 4 x

= 2 x^{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= 2 x^{2} + 4 x + C

\int_{0}^{4} x 19 - x^{2} d x

\int_{0}^{\frac{1}{2}} \frac{4}{3} (1 - x^{3}) d x

\int_{0}^{10} x^{2} d x

\frac{d}{d x} (3 + e^{- 3 x} - 3 e^{- 3 x} x)

\frac{d}{d x} (\frac{- 11}{2 ( x - 2 ) ^{2}} - \frac{4}{x - 2})