What is the tangent of y=2x^2-3x+1,(3,10) ?

The tangent of y=2x^2-3x+1,(3,10) is y=9x-17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=2x^2-3x+1,(3,10)

tangent of

y = 2 x^{2} - 3 x + 1, (3, 10)

y = 9 x - 17

Solution steps

Find the slope of

y = 2 x^{2} - 3 x + 1 : \frac{d y}{d x} = 4 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9

Find the line with slope m=

9

and passing through

(3, 10) : y = 9 x - 17

y = 9 x - 17

What is the tangent of y=2x^2-3x+1,(3,10) ?
The tangent of y=2x^2-3x+1,(3,10) is y=9x-17