What is the derivative of-8sin(8x) ?

The derivative of-8sin(8x) is -64cos(8x)

What is the first derivative of-8sin(8x) ?

The first derivative of-8sin(8x) is -64cos(8x)

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\frac{d}{d x} (- 8 sin (8 x))

- 64 cos (8 x)

Solution steps

\frac{d}{d x} (- 8 sin (8 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (sin (8 x))

Apply the chain rule:

cos (8 x) \frac{d}{d x} (8 x)

= cos (8 x) \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= - 8 cos (8 x) \cdot 8

Simplify

= - 64 cos (8 x)

What is the derivative of-8sin(8x) ?
The derivative of-8sin(8x) is -64cos(8x)
What is the first derivative of-8sin(8x) ?
The first derivative of-8sin(8x) is -64cos(8x)