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Beliebt Rechnen >

sum from n=0 to infinity of-1/(3^n)

Lösung

n = 0 \sum \infty - \frac{1}{3 ^{n}}

Lösung

- \frac{3}{2}

+1

Dezimale

- 1.5

Schritte zur Lösung

n = 0 \sum \infty - \frac{1}{3 ^{n}}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - n = 0 \sum \infty \frac{1}{3 ^{n}}

Geometrischen Test der Reihe anwenden:

\frac{3}{2}

= - \frac{3}{2}

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integral of (x^2)/(x^3+5)

\int \frac{x ^{2}}{x ^{3} + 5} d x

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sum from n=0 to infinity of (e/(6pi))^n

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