What is the solution for y^'= x/(3y) ?

The solution for y^'= x/(3y) is y=sqrt((x^2)/3+c_{1)},y=-sqrt((x^2)/3+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'= x/(3y)

y^{^{'}} = \frac{x}{3 y}

y = \frac{x ^{2}}{3} + c_{1}, y = - \frac{x ^{2}}{3} + c_{1}

Solution steps

y^{'} (x) = \frac{x}{3 y}

Solve separable ODE:

y = \frac{x ^{2}}{3} + c_{1}, y = - \frac{x ^{2}}{3} + c_{1}

y = \frac{x ^{2}}{3} + c_{1}, y = - \frac{x ^{2}}{3} + c_{1}

What is the solution for y^'= x/(3y) ?
The solution for y^'= x/(3y) is y=sqrt((x^2)/3+c_{1)},y=-sqrt((x^2)/3+c_{1)}