What is the derivative of f(x)=(x^2-1)/(x+1) ?

The derivative of f(x)=(x^2-1)/(x+1) is 1

What is the first derivative of f(x)=(x^2-1)/(x+1) ?

The first derivative of f(x)=(x^2-1)/(x+1) is 1

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derivative of

f (x) = \frac{x ^{2} - 1}{x + 1}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x + 1})

Simplify

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

What is the derivative of f(x)=(x^2-1)/(x+1) ?
The derivative of f(x)=(x^2-1)/(x+1) is 1
What is the first derivative of f(x)=(x^2-1)/(x+1) ?
The first derivative of f(x)=(x^2-1)/(x+1) is 1