taylor xe^{x^2},0

Lösung

taylor

x e^{x^{2}}, 0

x + x^{3} + \frac{1}{2} x^{5} + \frac{1}{6} x^{7} + \frac{1}{24} x^{9} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( x e ^{x^{2}} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x e ^{x^{2}} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x e ^{x^{2}} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{6}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{60}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{840}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{15120}{9 !} x^{9} + \dots

Fasse zusammen

= x + x^{3} + \frac{1}{2} x^{5} + \frac{1}{6} x^{7} + \frac{1}{24} x^{9} + \dots

\int \frac{21}{4 + 25 r ^{2}} d r

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x \to - 5 lim (g (x))