d/(dt)((3y^2-t^2)/(y^5))

Lösung

\frac{d}{d t} (\frac{3 y ^{2} - t ^{2}}{y ^{5}})

\frac{5 t ^{2} \frac{d y}{d t} - 2 t y - 9 y ^{2} \frac{d y}{d t}}{y ^{6}}

Schritte zur Lösung

\frac{d}{d t} (\frac{3 y ^{2} - t ^{2}}{y ^{5}})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d t} ( 3 y ^{2} - t ^{2} ) y ^{5} - \frac{d}{d t} ( y ^{5} ) ( 3 y ^{2} - t ^{2} )}{( y ^{5} ) ^{2}}

\frac{d}{d t} (3 y^{2} - t^{2}) = 6 y \frac{d y}{d t} - 2 t

\frac{d}{d t} (y^{5}) = 5 y^{4} \frac{d y}{d t}

= \frac{( 6 y \frac{d y}{d t} - 2 t ) y ^{5} - 5 y ^{4} \frac{d y}{d t} ( 3 y ^{2} - t ^{2} )}{( y ^{5} ) ^{2}}

Vereinfache

\frac{( 6 y \frac{d y}{d t} - 2 t ) y ^{5} - 5 y ^{4} \frac{d y}{d t} ( 3 y ^{2} - t ^{2} )}{( y ^{5} ) ^{2}} : \frac{5 t ^{2} \frac{d y}{d t} - 2 t y - 9 y ^{2} \frac{d y}{d t}}{y ^{6}}

= \frac{5 t ^{2} \frac{d y}{d t} - 2 t y - 9 y ^{2} \frac{d y}{d t}}{y ^{6}}

\frac{d}{d x} (ln (\frac{4}{x x + 1}))

\frac{\partial}{\partial x} (- 2 x y)

\frac{d}{d x} ((x^{3} - 4 x + 1) e^{x})

x \to 0 lim (\frac{5}{tan ( 3 x )})

8 \frac{d y}{d x} + 7 e^{x + y} = 0