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Beliebt Rechnen >

integral of 2x(x^2-1)^3

Lösung

\int 2 x (x^{2} - 1)^{3} d x

Lösung

\frac{x ^{8}}{4} - x^{6} + \frac{3 x ^{4}}{2} - x^{2} + C

Schritte zur Lösung

\int 2 x (x^{2} - 1)^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} - 1)^{3} d x

Multipliziere aus

x (x^{2} - 1)^{3} : x^{7} - 3 x^{5} + 3 x^{3} - x

= 2 \cdot \int x^{7} - 3 x^{5} + 3 x^{3} - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int x^{7} d x - \int 3 x^{5} d x + \int 3 x^{3} d x - \int x d x)

\int x^{7} d x = \frac{x ^{8}}{8}

\int 3 x^{5} d x = \frac{x ^{6}}{2}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int x d x = \frac{x ^{2}}{2}

= 2 (\frac{x ^{8}}{8} - \frac{x ^{6}}{2} + \frac{3 x ^{4}}{4} - \frac{x ^{2}}{2})

Vereinfache

2 (\frac{x ^{8}}{8} - \frac{x ^{6}}{2} + \frac{3 x ^{4}}{4} - \frac{x ^{2}}{2}) : \frac{x ^{8}}{4} - x^{6} + \frac{3 x ^{4}}{2} - x^{2}

= \frac{x ^{8}}{4} - x^{6} + \frac{3 x ^{4}}{2} - x^{2}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{8}}{4} - x^{6} + \frac{3 x ^{4}}{2} - x^{2} + C

Graph

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