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tangent f(x)=7e^xcos(x),\at x=0

解答

切线

f (x) = 7 e^{x} cos (x), at x = 0

解答

y = 7 x + 7

求解步骤

找到切点:

(0, 7)

计算

f (x) = 7 e^{x} cos (x)

的斜率:

\frac{df ( x )}{d x} = 7 (e^{x} cos (x) - e^{x} sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

找到斜率 m=

7

且穿过

(0, 7)

的直线:

y = 7 x + 7

y = 7 x + 7

作图

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