integral of (xarctan(x^2))/(1+x^4)

Lösung

\int \frac{x arctan ( x ^{2} )}{1 + x ^{4}} d x

\frac{1}{4} arctan^{2} (x^{2}) + C

Schritte zur Lösung

\int \frac{x arctan ( x ^{2} )}{1 + x ^{4}} d x

Wende U-Substitution an

= \int \frac{arctan ( u )}{2 ( 1 + u ^{2} )} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{arctan ( u )}{1 + u ^{2}} d u

Wende U-Substitution an

= \frac{1}{2} \cdot \int v d v

Wende die Potenzregel an

= \frac{1}{2} \cdot \frac{v ^{2}}{2}

Ersetze zurück

= \frac{1}{2} \cdot \frac{arctan ^{2} ( x ^{2} )}{2}

Vereinfache

\frac{1}{2} \cdot \frac{arctan ^{2} ( x ^{2} )}{2} : \frac{1}{4} arctan^{2} (x^{2})

= \frac{1}{4} arctan^{2} (x^{2})

Füge eine Konstante zur Lösung hinzu

= \frac{1}{4} arctan^{2} (x^{2}) + C

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