What is the integral of (7x)/(e^{2x)} ?

The integral of (7x)/(e^{2x)} is 7(-1/2 e^{-2x}x-1/4 e^{-2x})+C

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integral of (7x)/(e^{2x)}

\int \frac{7 x}{e ^{2 x}} d x

7 (- \frac{1}{2} e^{- 2 x} x - \frac{1}{4} e^{- 2 x}) + C

Solution steps

\int \frac{7 x}{e ^{2 x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{x}{e ^{2 x}} d x

Apply Integration By Parts

= 7 (- \frac{1}{2} e^{- 2 x} x - \int - \frac{1}{2} e^{- 2 x} d x)

\int - \frac{1}{2} e^{- 2 x} d x = \frac{1}{4} e^{- 2 x}

= 7 (- \frac{1}{2} e^{- 2 x} x - \frac{1}{4} e^{- 2 x})

Add a constant to the solution

= 7 (- \frac{1}{2} e^{- 2 x} x - \frac{1}{4} e^{- 2 x}) + C

What is the integral of (7x)/(e^{2x)} ?
The integral of (7x)/(e^{2x)} is 7(-1/2 e^{-2x}x-1/4 e^{-2x})+C