What is the integral of sin(6x-7) ?

The integral of sin(6x-7) is -1/6 cos(6x-7)+C

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integral of sin(6x-7)

\int sin (6 x - 7) d x

- \frac{1}{6} cos (6 x - 7) + C

Solution steps

\int sin (6 x - 7) d x

Apply u-substitution

= \int sin (u) \frac{1}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{6} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{6} (- cos (u))

Substitute back

u = 6 x - 7

= \frac{1}{6} (- cos (6 x - 7))

Simplify

= - \frac{1}{6} cos (6 x - 7)

Add a constant to the solution

= - \frac{1}{6} cos (6 x - 7) + C

What is the integral of sin(6x-7) ?
The integral of sin(6x-7) is -1/6 cos(6x-7)+C