derivative \sqrt[3]{6+2x+x^3}

Lösung

ableitung von

3 6 + 2 x + x^{3}

\frac{3 x ^{2} + 2}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}}

Schritte zur Lösung

\frac{d}{d x} (3 6 + 2 x + x^{3})

Wende die Kettenregel an:

\frac{1}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}} \frac{d}{d x} (6 + 2 x + x^{3})

= \frac{1}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}} \frac{d}{d x} (6 + 2 x + x^{3})

\frac{d}{d x} (6 + 2 x + x^{3}) = 3 x^{2} + 2

= \frac{1}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}} (3 x^{2} + 2)

Vereinfache

\frac{1}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}} (3 x^{2} + 2) : \frac{3 x ^{2} + 2}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}}

= \frac{3 x ^{2} + 2}{3 ( 6 + 2 x + x ^{3} ) ^{\frac{2}{3}}}

\frac{d}{d x} (csc^{2} (1 - 2 x))

x \to - 1 lim (3 x^{4} - 6 x + 1)

\int 3 x^{2} + 2 x d x

x \to 2 lim (x^{3} - 5 x)

x \to - 6 + lim (x + 6)