integral of arcsec(m)x

Lösung

\int arcsec (m) x d x

\frac{1}{2} x^{2} arcsec (m) + C

Schritte zur Lösung

\int arcsec (m) x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= arcsec (m) \cdot \int x d x

Wende die Potenzregel an

= arcsec (m) \frac{x ^{2}}{2}

Vereinfache

arcsec (m) \frac{x ^{2}}{2} : \frac{1}{2} x^{2} arcsec (m)

= \frac{1}{2} x^{2} arcsec (m)

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} x^{2} arcsec (m) + C

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