What is the integral of (1+tan(x))sec^2(x) ?

The integral of (1+tan(x))sec^2(x) is ((1+tan(x))^2)/2+C

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integral of (1+tan(x))sec^2(x)

\int (1 + tan (x)) sec^{2} (x) d x

\frac{( 1 + tan ( x ) ) ^{2}}{2} + C

Solution steps

\int (1 + tan (x)) sec^{2} (x) d x

Apply u-substitution

= \int u d u

Apply the Power Rule

= \frac{u ^{2}}{2}

Substitute back

u = 1 + tan (x)

= \frac{( 1 + tan ( x ) ) ^{2}}{2}

Add a constant to the solution

= \frac{( 1 + tan ( x ) ) ^{2}}{2} + C

What is the integral of (1+tan(x))sec^2(x) ?
The integral of (1+tan(x))sec^2(x) is ((1+tan(x))^2)/2+C