What is the integral of 1/(1+(x-5)^2) ?

The integral of 1/(1+(x-5)^2) is arctan(x-5)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(1+(x-5)^2)

\int \frac{1}{1 + ( x - 5 ) ^{2}} d x

arctan (x - 5) + C

Solution steps

\int \frac{1}{1 + ( x - 5 ) ^{2}} d x

Apply u-substitution

= \int \frac{1}{1 + u ^{2}} d u

Use the common integral:

\int \frac{1}{1 + u ^{2}} d u = arctan (u)

= arctan (u)

Substitute back

u = x - 5

= arctan (x - 5)

Add a constant to the solution

= arctan (x - 5) + C

What is the integral of 1/(1+(x-5)^2) ?
The integral of 1/(1+(x-5)^2) is arctan(x-5)+C