What is the integral of e^{1+x^2} ?

The integral of e^{1+x^2} is e(sqrt(pi))/2 \erfi(x)+C

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integral of e^{1+x^2}

\int e^{1 + x^{2}} d x

e \frac{π}{2} erfi (x) + C

Solution steps

\int e^{1 + x^{2}} d x

e^{1 + x^{2}} = e^{1} e^{x^{2}}

= \int e^{1} e^{x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{1} \cdot \int e^{x^{2}} d x

Simplify

= e \cdot \int e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= e \frac{π}{2} erfi (x)

Add a constant to the solution

= e \frac{π}{2} erfi (x) + C

What is the integral of e^{1+x^2} ?
The integral of e^{1+x^2} is e(sqrt(pi))/2 \erfi(x)+C