What is the integral of x^2(3x+2) ?

The integral of x^2(3x+2) is (3x^4)/4+(2x^3)/3+C

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integral of x^2(3x+2)

\int x^{2} (3 x + 2) d x

\frac{3 x ^{4}}{4} + \frac{2 x ^{3}}{3} + C

Solution steps

\int x^{2} (3 x + 2) d x

Expand

x^{2} (3 x + 2) : 3 x^{3} + 2 x^{2}

= \int 3 x^{3} + 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{3} d x + \int 2 x^{2} d x

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

= \frac{3 x ^{4}}{4} + \frac{2 x ^{3}}{3}

Add a constant to the solution

= \frac{3 x ^{4}}{4} + \frac{2 x ^{3}}{3} + C

What is the integral of x^2(3x+2) ?
The integral of x^2(3x+2) is (3x^4)/4+(2x^3)/3+C