What is the integral of ((10)/(x^2)) ?

The integral of ((10)/(x^2)) is -(10)/x+C

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integral of ((10)/(x^2))

\int (\frac{10}{x ^{2}}) d x

- \frac{10}{x} + C

Solution steps

\int \frac{10}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= 10 (- \frac{1}{x})

Simplify

10 (- \frac{1}{x}) : - \frac{10}{x}

= - \frac{10}{x}

Add a constant to the solution

= - \frac{10}{x} + C

What is the integral of ((10)/(x^2)) ?
The integral of ((10)/(x^2)) is -(10)/x+C