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Popular Calculus >

integral from 0 to 6 of (3x^2+1)

Solution

\int_{0}^{6} (3 x^{2} + 1) d x

Solution

222

Solution steps

\int_{0}^{6} 3 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} 3 x^{2} d x + \int_{0}^{6} 1 d x

\int_{0}^{6} 3 x^{2} d x = 216

\int_{0}^{6} 1 d x = 6

= 216 + 6

Simplify

= 222

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 6 of (3x^2+1) ?
The integral from 0 to 6 of (3x^2+1) is 222