integral from 1/2 to 1 of (x^{-3}-7)

Lösung

\int_{\frac{1}{2}}^{1} (x^{- 3} - 7) d x

- 2

Schritte zur Lösung

\int_{\frac{1}{2}}^{1} x^{- 3} - 7 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{\frac{1}{2}}^{1} x^{- 3} d x - \int_{\frac{1}{2}}^{1} 7 d x

\int_{\frac{1}{2}}^{1} x^{- 3} d x = \frac{3}{2}

\int_{\frac{1}{2}}^{1} 7 d x = \frac{7}{2}

= \frac{3}{2} - \frac{7}{2}

Vereinfache

\frac{3}{2} - \frac{7}{2} : - 2

= - 2

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