integral from 0 to pi/4 of 2cos(x)+1

Lösung

\int_{0}^{\frac{π}{4}} 2 cos (x) + 1 d x

2 + \frac{π}{4}

Dezimale

2.19961 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{4}} 2 cos (x) + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{4}} 2 cos (x) d x + \int_{0}^{\frac{π}{4}} 1 d x

\int_{0}^{\frac{π}{4}} 2 cos (x) d x = 2

\int_{0}^{\frac{π}{4}} 1 d x = \frac{π}{4}

= 2 + \frac{π}{4}

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