What is the integral from-1 to 1 of (x)^2 ?

The integral from-1 to 1 of (x)^2 is 2/3

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integral from-1 to 1 of (x)^2

\int_{- 1}^{1} (x)^{2} d x

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} d x

Apply the Power Rule

= [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

\int_{0}^{x^{2}} cos (t^{3}) d t

\int_{0}^{\frac{π}{3}} 2 cos (x) d x

\int_{0}^{2} 5^{3 x} d x

\int_{0}^{2} (2 x^{3} - 2 x) d x

\int_{1}^{3} 2^{5 x} d x

What is the integral from-1 to 1 of (x)^2 ?
The integral from-1 to 1 of (x)^2 is 2/3