integral from 1 to 2 of 1/(1+x^2)

Lösung

\int_{1}^{2} \frac{1}{1 + x ^{2}} d x

arctan (2) - \frac{π}{4}

Dezimale

0.32175 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{1}^{2}

Berechne die Grenzen:

arctan (2) - \frac{π}{4}

= arctan (2) - \frac{π}{4}