integral from 1 to 4 of (x+x^2)

Lösung

\int_{1}^{4} (x + x^{2}) d x

\frac{57}{2}

Dezimale

28.5

Schritte zur Lösung

\int_{1}^{4} x + x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x d x + \int_{1}^{4} x^{2} d x

\int_{1}^{4} x d x = \frac{15}{2}

\int_{1}^{4} x^{2} d x = 21

= \frac{15}{2} + 21

Vereinfache

\frac{15}{2} + 21 : \frac{57}{2}

= \frac{57}{2}