slopeintercept (0,2),(-5,-1)

解答

斜率截距

(0, 2), (- 5, - 1)

y = \frac{3}{5} x + 2

求解步骤

计算斜率

(0, 2), (- 5, - 1) : m = \frac{3}{5}

计算

y

轴截距:

b = 2

构建直线方程

y = mx + b

其中

m = \frac{3}{5}

且

b = 2

y = \frac{3}{5} x + 2

in v erse l a pl a ce e^{- s} \frac{1}{s - 4}

x \to \infty + lim (\frac{2 x + 1}{4 x ^{2} + x})

\frac{y}{x} \cdot \frac{d y}{d x} = - 4 - \frac{y ^{2}}{x ^{2}}

x \to 3 lim (\frac{1}{x})

x y^{^{'}} - y = \frac{x ^{2}}{y} e^{\frac{y}{x}}