integral from 1 to 1.5 of (2x+3/(2x^2))

Lösung

\int_{1}^{1.5} (2 x + \frac{3}{2 x ^{2}}) d x

1.75

Schritte zur Lösung

\int_{1}^{1.5} 2 x + \frac{3}{2 x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{1.5} 2 x d x + \int_{1}^{1.5} \frac{3}{2 x ^{2}} d x

\int_{1}^{1.5} 2 x d x = 1.25

\int_{1}^{1.5} \frac{3}{2 x ^{2}} d x = 0.5

= 1.25 + 0.5

Vereinfache

= 1.75

\int_{1}^{5} (x + 1) (x^{2} + 2 x)^{2} d x

\int_{0}^{\frac{π}{4}} cos (x) + 1 d x

\int_{- 1}^{0} (2 x + 5)^{3} d x

\int_{0}^{\frac{π}{4}} sec^{2} (x) e^{t a n (x)} d x

\int_{2}^{x} t^{4} d t