integral from 1 to infinity of (1/x)^2

Lösung

\int_{1}^{\infty} (\frac{1}{x})^{2} d x

1

Schritte zur Lösung

\int_{1}^{\infty} (\frac{1}{x})^{2} d x

Berechne das unbestimmte Integral:

\int (\frac{1}{x})^{2} d x = - \frac{1}{x} + C

Berechne die Grenzen:

\int_{1}^{\infty} (\frac{1}{x})^{2} d x = 0 - (- 1)

= 0 - (- 1)

Vereinfache

= 1

\int_{3 x}^{x^{3}} e^{- t^{2}} d t

\int_{- 1}^{0} - x - x^{2} d x

\int_{1 - i}^{2 i} z^{2} - 6 - 4 i z d z

\int_{1}^{2} (24 x^{3} + \frac{6}{x ^{2}}) d x

\int_{0}^{10} t e^{- 0.2 t} d t