integral from 0 to 2 of sqrt(2x+5)

Lösung

\int_{0}^{2} 2 x + 5 d x

\frac{27 - 5 5}{3}

Dezimale

5.27322 \dots

Schritte zur Lösung

\int_{0}^{2} 2 x + 5 d x

Wende U-Substitution an

= \int_{5}^{9} \frac{u}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{5}^{9} u d u

Wende die Potenzregel an

= \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{5}^{9}

Berechne die Grenzen:

18 - \frac{10 5}{3}

= \frac{1}{2} (18 - \frac{10 5}{3})

Vereinfache

= \frac{27 - 5 5}{3}

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