limit as x approaches-infinity of \sqrt[x]{2}

解答

x \to - \infty lim (x 2)

1

求解步骤

x \to - \infty lim (x 2)

使用指数运算法则

= x \to - \infty lim (e^{\frac{1}{x} l n (2)})

化简

e^{\frac{1}{x} l n (2)} : 2^{\frac{1}{x}}

= x \to - \infty lim (2^{\frac{1}{x}})

使用指数运算法则

= x \to - \infty lim (e^{\frac{1}{x} l n (2)})

使用极限链式法则:

1

= 1

t an g e n t f (x) = x^{2} + 9, (- 4, 25)

\int 10 e^{- 10 x} d x

\int - \frac{8}{π} x d x

y^{^{'}} = 0.06 (y - 65)

\frac{2 \cdot d y}{d x} + 100 \cdot y = 30 \cdot sin (60 x), y (0) = 0