integral from 0 to 2 of xcos(npix)

Lösung

\int_{0}^{2} x cos (nπ x) d x

\frac{2 sin ( 2 πn )}{πn}

Schritte zur Lösung

\int_{0}^{2} x cos (nπ x) d x

Wende U-Substitution an

= \int_{0}^{n \cdot 2 π} \frac{u cos ( u )}{π ^{2} n ^{2}} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{π ^{2} n ^{2}} \cdot \int_{0}^{n \cdot 2 π} u cos (u) d u

Wende die partielle Integration an

= \frac{1}{π ^{2} n ^{2}} [u sin (u) - \int sin (u) d u]_{0}^{2 πn}

\int sin (u) d u = - cos (u)

= \frac{1}{π ^{2} n ^{2}} [u sin (u) - (- cos (u))]_{0}^{2 πn}

Vereinfache

= \frac{1}{π ^{2} n ^{2}} [u sin (u) + cos (u)]_{0}^{2 πn}

Berechne die Grenzen:

2 πn sin (2 πn)

= \frac{1}{π ^{2} n ^{2}} \cdot 2 πn sin (2 πn)

Vereinfache

= \frac{2 sin ( 2 πn )}{πn}

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