integral from 0 to 3 of (x^3-4x)

Lösung

\int_{0}^{3} (x^{3} - 4 x) d x

\frac{9}{4}

Dezimale

2.25

Schritte zur Lösung

\int_{0}^{3} x^{3} - 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{3} d x - \int_{0}^{3} 4 x d x

\int_{0}^{3} x^{3} d x = \frac{81}{4}

\int_{0}^{3} 4 x d x = 18

= \frac{81}{4} - 18

Vereinfache

\frac{81}{4} - 18 : \frac{9}{4}

= \frac{9}{4}

\int_{0}^{3} \frac{3}{x + 4} d x

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\int_{0}^{5} e^{- x^{2}} d x

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