integral from 3 to 6 of g(x)

Lösung

\int_{3}^{6} g (x) d x

\frac{27 g}{2}

Schritte zur Lösung

\int_{3}^{6} gx d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{3}^{6} x d x

Wende die Potenzregel an

= g [\frac{x ^{2}}{2}]_{3}^{6}

Berechne die Grenzen:

\frac{27}{2}

= g \frac{27}{2}

Vereinfache

= \frac{27 g}{2}

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