integral from-1 to 1 of (x+|x|)^2

Lösung

\int_{- 1}^{1} (x + ∣ x ∣)^{2} d x

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} (x + ∣ x ∣)^{2} d x

Entferne die Extremwerte

= \int_{- 1}^{0} (x - x)^{2} d x + \int_{0}^{1} (x + x)^{2} d x

\int_{- 1}^{0} (x - x)^{2} d x = 0

\int_{0}^{1} (x + x)^{2} d x = \frac{4}{3}

= 0 + \frac{4}{3}

Vereinfache

= \frac{4}{3}

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