integral from 1 to 2 of x+1/x

Lösung

\int_{1}^{2} x + \frac{1}{x} d x

\frac{3}{2} + ln (2)

Dezimale

2.19314 \dots

Schritte zur Lösung

\int_{1}^{2} x + \frac{1}{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d x + \int_{1}^{2} \frac{1}{x} d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} \frac{1}{x} d x = ln (2)

= \frac{3}{2} + ln (2)

\int_{x^{2}}^{x} x y^{2} d y

\int_{2}^{3} 2^{- x} d x

\int_{0}^{1} x e^{t x} d x

\int_{0}^{\frac{1}{2} l n (5)} e^{x} d x

\int_{0}^{2} x (x - 7) d x