integral from 1 to 4 of (x^2-x)

Lösung

\int_{1}^{4} (x^{2} - x) d x

\frac{27}{2}

Dezimale

13.5

Schritte zur Lösung

\int_{1}^{4} x^{2} - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x - \int_{1}^{4} x d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} x d x = \frac{15}{2}

= 21 - \frac{15}{2}

Vereinfache

21 - \frac{15}{2} : \frac{27}{2}

= \frac{27}{2}

\int_{\frac{- π}{2}}^{\frac{π}{2}} cos (2 x) d x

\int_{- 1}^{4} \frac{1}{x ^{2} + x - 2} d x

\int_{2}^{6} 3 d x

\int_{0}^{3} 3 x^{2} - 3 d x

\int_{0}^{2} (3 - x) x d x