integral from 1 to 4 of (x^2+6)

Lösung

\int_{1}^{4} (x^{2} + 6) d x

39

Schritte zur Lösung

\int_{1}^{4} x^{2} + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} 6 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 6 d x = 18

= 21 + 18

Vereinfache

= 39

\int_{3}^{x^{2}} \frac{1}{t ^{4}} d t

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