What is the integral from 2 to 4 of 3/x-6/(x^2) ?

The integral from 2 to 4 of 3/x-6/(x^2) is 3ln(2)-3/2

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integral from 2 to 4 of 3/x-6/(x^2)

\int_{2}^{4} \frac{3}{x} - \frac{6}{x ^{2}} d x

3 ln (2) - \frac{3}{2}

Decimal

0.57944 \dots

Solution steps

\int_{2}^{4} \frac{3}{x} - \frac{6}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} \frac{3}{x} d x - \int_{2}^{4} \frac{6}{x ^{2}} d x

\int_{2}^{4} \frac{3}{x} d x = 3 ln (2)

\int_{2}^{4} \frac{6}{x ^{2}} d x = \frac{3}{2}

= 3 ln (2) - \frac{3}{2}

What is the integral from 2 to 4 of 3/x-6/(x^2) ?
The integral from 2 to 4 of 3/x-6/(x^2) is 3ln(2)-3/2