integral from-1 to 4 of (x+1)

Lösung

\int_{- 1}^{4} (x + 1) d x

\frac{25}{2}

Dezimale

12.5

Schritte zur Lösung

\int_{- 1}^{4} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{4} x d x + \int_{- 1}^{4} 1 d x

\int_{- 1}^{4} x d x = \frac{15}{2}

\int_{- 1}^{4} 1 d x = 5

= \frac{15}{2} + 5

Vereinfache

\frac{15}{2} + 5 : \frac{25}{2}

= \frac{25}{2}

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