integral from 0 to 5 of (13)/(sqrt(x+4))

Lösung

\int_{0}^{5} \frac{13}{x + 4} d x

26

Schritte zur Lösung

\int_{0}^{5} \frac{13}{x + 4} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 13 \cdot \int_{0}^{5} \frac{1}{x + 4} d x

Wende U-Substitution an

= 13 \cdot \int_{2}^{3} 2 d u

Integral einer Konstanten :

\int a d x = a x

= 13 [2 u]_{2}^{3}

Berechne die Grenzen:

2

= 13 \cdot 2

Vereinfache

= 26

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