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人気のある微分積分 >

integral from 1 to 2 of (6x^2-2x+1)

解

\int_{1}^{2} (6 x^{2} - 2 x + 1) d x

解

12

解答ステップ

\int_{1}^{2} 6 x^{2} - 2 x + 1 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 6 x^{2} d x - \int_{1}^{2} 2 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 6 x^{2} d x = 14

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 1 d x = 1

= 14 - 3 + 1

簡素化

= 12

グラフ

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