integral from 2 to 5 of 1/((x+4))

Lösung

\int_{2}^{5} \frac{1}{( x + 4 )} d x

ln (\frac{3}{2})

Dezimale

0.40546 \dots

Schritte zur Lösung

\int_{2}^{5} \frac{1}{x + 4} d x

Wende U-Substitution an

= \int_{6}^{9} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{6}^{9}

Berechne die Grenzen:

2 ln (3) - ln (6)

= 2 ln (3) - ln (6)

Vereinfache

= ln (\frac{3}{2})

\int_{1}^{4} x^{4} ln (x) d x

\int_{0}^{9} \frac{185}{( t + 1 ) ^{3}} d t

\int_{1}^{7} \frac{6}{1 - 3 x} d x

\int_{0}^{1} sin^{3} (x) d x

\int_{1}^{9} 7 u d u