derivative tan(4x^2-3x-4)

解答

导数

tan (4 x^{2} - 3 x - 4)

sec^{2} (4 x^{2} - 3 x - 4) (8 x - 3)

求解步骤

\frac{d}{d x} (tan (4 x^{2} - 3 x - 4))

使用连锁律:

sec^{2} (4 x^{2} - 3 x - 4) \frac{d}{d x} (4 x^{2} - 3 x - 4)

= sec^{2} (4 x^{2} - 3 x - 4) \frac{d}{d x} (4 x^{2} - 3 x - 4)

\frac{d}{d x} (4 x^{2} - 3 x - 4) = 8 x - 3

= sec^{2} (4 x^{2} - 3 x - 4) (8 x - 3)

\int \frac{3}{4} + \frac{4}{5} x^{2} - \frac{5}{6} x^{3} d x

d er i v a t i v e 5 x + 7 x

x \to 2 lim (3 \frac{x ^{3} - 8}{x - 2})

t a y l or 1 + x

\frac{d}{d x} (\frac{e ^{x} + 1}{e ^{x} + 2})